(probability of you being unfunny) / ∞ = your Probability of getting head
02-07-2011 at 04:13 PM
#6
PHLN
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Quote:
Originally Posted by Desda
If I toss a coin, what's the probability of me getting head?
Kthx.
:po op:
Its "choices you want"/"choices available".
So in a coin, for head, the choice you want is 1. Choices available is 2, either head or tail.
As such, the probability of you getting head is 1/2. or 50% chance.
If you want, I am available for personal tutoring. Once we finish a session over drinks, you should be able to calculate my chances of getting head by yourself.
02-07-2011 at 04:36 PM
#7
Desda
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Quote:
Originally Posted by Drizzzy
no its
(probability of you being unfunny) / ∞ = your Probability of getting head
Lol, how many times have you gotten banned, Juve?
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02-07-2011 at 06:20 PM
#8
Bhaltair
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Quote:
Originally Posted by PHLN
Its "choices you want"/"choices available".
So in a coin, for head, the choice you want is 1. Choices available is 2, either head or tail.
As such, the probability of you getting head is 1/2. or 50% chance.
If you want, I am available for personal tutoring. Once we finish a session over drinks, you should be able to calculate my chances of getting head by yourself.
Actually, it's about 45% chance since the heads weights more than tails.
Blame Queen Elizabeth's face.
Ideally, it is 50%.
02-07-2011 at 06:23 PM
#9
lawleypop
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Quote:
Originally Posted by Bhaltair
Actually, it's about 45% chance since the heads weights more than tails.
Blame Queen Elizabeth's face.
Ideally, it is 50%.
I really don't believe that such an insignificant weight difference could affect the probabilities by THAT much... I feel like 49.90% or something would be more believable.
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Mathematically it makes about as much sense as (pineapple)$$*cucumbe r*.
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