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The question is a bit annoying because they don't give you initial values, but all you need to figure out both values you haven't solved for yet is the total travel time.
Finding the time isn't particularly difficult, just use the Vf^2+Vi^2+2ad equation and solve for Vf (Starting from the max height, we know Vi = 0m/s, a = -9.8m/s/s, and d = 8.95m). Once you have Vf, plug it into the Vf=Vi+a*t equation and solve for t. The t that you solve for here is the time it takes for the ball to drop from it's max height back to the ground, which will be exactly half the time the ball will be in the air.
Horizontal distance traveled is just df = di+v*(2t) where v is the given horizontal vector (Haven't taken physics in 3 years so I can't remember if j or i is horizontal) and di=0. Also, remember we're using 2t because the t we calculated earlier is only half the total travel time.
Final velocity is just pluging the vf and horizontal v from earlier into the Pythagorean theorem.
Hope that helps.
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Masters Biochemistry
Honours Biology and Psychology
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