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Physics 1B03 Capa Help

 
Old 04-05-2011 at 08:20 PM   #61
Faer
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Quote:
Originally Posted by justinsftw View Post
Lulz. Check the homepage for Physics on Avenue.
Hahaha...how did I miss that? LOL. It wasn't posted up earlier today...hahaha, that's amazing.

I still did mine because he didn't confirm it wasn't for marks, so...this is hilarious. Poor people who haven't done it. O_O
Old 04-05-2011 at 08:34 PM   #62
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^ Got it, thanks!
Old 04-05-2011 at 09:50 PM   #63
Chevalier
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hey can someone help me with these 2 q;s...


A fresh water pond that is 16.2 m deep is contained on one side by a cliff. The water has eroded a nearly horizontal "tube" through a bed of limestone, which allows the water to emerge on the other side of the cliff. If the "tube" has a diameter of 4.17 cm, and is located 6.0 m below the surface of the pond, what is the frictional force between the "tube" wall and a rock that is blocking the exit?

Last edited by Chevalier : 04-05-2011 at 09:56 PM.
Old 04-05-2011 at 10:01 PM   #64
Faer
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For the first, I believe it's a simple application of the Continuity formula. v2A2=v1A1. Try that, I don't quite remember...

As for the second...you need to find the pressure difference at the point where the rock is, because force = pressure x Area.

Pressure along a horizontal line is the same. So the pressure along the pond side of the rock is the same as the pressure of the water at a depth of 6m.

The pressure on the other side of the rock (the cliff side) is just the atmospheric pressure. You can find the area since the diameter is given, and hence find force.

For the second part of that (q.11?), you need to find the flow rate, Q=vA. You can find velocity using Bernoulli's equation, and area is given. Just multiply that with time.

Hope that helped!
Old 04-05-2011 at 10:16 PM   #65
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haha yep i got it thx... for 10 i did it a bit differently but i think urs works too..now just #9 to go lol im cutting it close -_-
Old 04-05-2011 at 10:26 PM   #66
Faer
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Just find the pressure difference p2-p1. Since the tube is horizontal, y=0, so you just need to basically find 1/2rhov1^2-1/2rhov2^2.

After getting the pressure difference, just multiply it with the area to get the force!

(I think that's right, I didn't actually see the question, just my working, LOL. Hope it helps! And good luck...34 minutes to go... )

EDIT: Oops, did you even ask help for that? O__O LOL.



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