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What am I doing wrong?

 
Old 10-17-2014 at 08:46 PM   #1
dshishir42
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What am I doing wrong?
y=sinx
=1/(sinx)^-1
dy/dx = 1/(-1*(sinx)^-2)*cosx
=-(sinx)^2/cosx


dy/dx of sinx = cosx

How is cosx equal to -(sinx)^2/cosx? Is it equal to it? Cuz I been trying for like an hour, and it just doesn't make sense! I dont see that I did anything wrong. And it is just basic math..

Last edited by dshishir42 : 10-17-2014 at 08:53 PM.
Old 10-17-2014 at 09:10 PM   #2
dshishir42
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Solved it..
Old 10-17-2014 at 09:11 PM   #3
Serene
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You didn't take the derivative correctly from line 2 to 3.
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Old 10-18-2014 at 10:57 AM   #4
GeorgeLucas
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You need to cancel out the s and x terms So you are gonna get:

=-(sinx)^2/cosx

= -(in)^2/co
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