Couldn't find it all over the net... or if I could, I get the same answer... So was wondering if anyone with some physics knowledge would be able to see what I'm doing wrong....
A 113 kg chesterfield is pushed up a frictionless ramp at a constant speed by a delivery person. If the ramp is inclined at 29.2° to the horizontal, what horizontal force must the delivery person apply to the chesterfield? <--- got this part right (6.20e2 N)
What is the magnitude of the normal force that is exerted on the chesterfield by the ramp?!?!?!
This is what I keep doing and have tried all sorts of sig figs... Here's my work... (@ = theta)
F=mg=113*9.81
Fn=mg*cos(@)
=113*9.81*cos29.2
=967 N
Any help?
Please and thank you!
10-03-2011 at 07:19 PM
#2
britb
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Quote:
Originally Posted by patela77
Couldn't find it all over the net... or if I could, I get the same answer... So was wondering if anyone with some physics knowledge would be able to see what I'm doing wrong....
A 113 kg chesterfield is pushed up a frictionless ramp at a constant speed by a delivery person. If the ramp is inclined at 29.2° to the horizontal, what horizontal force must the delivery person apply to the chesterfield? <--- got this part right (6.20e2 N)
What is the magnitude of the normal force that is exerted on the chesterfield by the ramp?!?!?!
This is what I keep doing and have tried all sorts of sig figs... Here's my work... (@ = theta)
F=mg=113*9.81
Fn=mg*cos(@)
=113*9.81*cos29.2
=967 N
Any help?
Please and thank you!
Use Avenue. We are NOT here to do your homework, and we are certainly NOT here to help you cheat on CAPA. You have a number of resources for this course - use them.
10-03-2011 at 07:34 PM
#3
VastHorizon
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Remember that the normal force is perpendicular to your surface and that it is a vector.
It should have x and y components and you're taking the magnitude of it.
Which in your case is just...
Hope this helps.
Last edited by VastHorizon : 10-03-2011 at 07:37 PM.
10-03-2011 at 07:36 PM
#4
patela77
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Quote:
Originally Posted by britb
Use Avenue. We are NOT here to do your homework, and we are certainly NOT here to help you cheat on CAPA. You have a number of resources for this course - use them.
not a problem. just thought i could put it out there since i saw older posts of people helping others on capa.
10-03-2011 at 07:36 PM
#5
Leeoku
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capa was the worst part of eng1
10-03-2011 at 07:37 PM
#6
patela77
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Quote:
Originally Posted by VastHorizon
Remember that the normal force is perpendicular to your surface and that it is a vector.
It should have x and y components and you're taking the magnitude of it.
Which is just...
Hope this helps.
thanks for the help! seems easy enough.
10-03-2011 at 08:11 PM
#7
forever0zero
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i guess people aren't posting plug and play answers on capa anymore
10-03-2011 at 10:19 PM
#8
RyanC
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I would help you if I remembered this shit, sorry :(
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